So, i do a lot of electrical... mostly sterio stuff, and now im gunna be doing some leds in the car, and was wondering how to go about the wiring of these. as in, what type of resistor? how exactly to wire the LEDs in a car. never realy looked into and any help would be greatly appreciated,. thanks!!
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
Some LEDs are already 12V so you don't have to do anything. The other ones are 2V I believe and you will need a 1K Ohm resistor (If my memory didn't fail me). The LEDs have a positive and a negative, if you wire it backwards then they won't work. Can't really go wrong here.
Jay
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yeah i knew about the posative and negative, how theyre diodes and diodes are one way, but as for resistor size i didnt know, now if i wire a lot of these in seriese... or paralelle, whats the best way of going about that, cuz theres gunna be quite a few, and i want them to be equaly as bright
i appreciate your reply man! means a lot to see someone on teh org helping out, gotta love this place. and you realy did help me out here, so continue answering my LED newbie questions lol
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
wire in parralel. series just makes it confusing. put a small resistor on each positive side of each led. done.....as for resistor size. easiest way is to go to radioshack and find someone who knows their @!#$. they'll pick out the right one. thats what i did for my led chaser board i built
trust radio shacks advice on how to wire LEDs in a car's electrical system.. i honestly dont know if i trust their electrical advice outside of how to plug stuff in or wire LEDs in a computer.. witch is a completely different matter.... basicaly my questions are as follows, and have for the most part been almost answered completely by you guys lol. 1. what size resistor is neede when running LEDs in a car? 2. seriese or paralell to get equal lighting from each LED? would greatly appreciate all the help,.... and as for you Mr Machzel.. how u been man? been a while since i talked to you after my vaca down there, speaking of that, was a blast!
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
Go to
http://www.lsdiodes.com. There is a tutorial and 2 resistance calculators there. Also, they have the cheapest LED's I've seen yet. Great quality too. If you have any questions, e-mail them, they're very helpful.
thanks bro, i appreciate it!
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
If you wire them in series, plus to minus, plus to minus, plus to minus, etc... the voltage will split. so if you wire 6 2 volt LEDs in this fassion, you will get a full 12v drop, and they will work find with no resistors. Granted the first will be the brightest and they will slowly fade. But it will work with no resistors.
And once you have this 6-LED chain made, you can the create more chains and wire them all in parrellel. And they will work.
You may want to check Ebay, my buddy got a bag of 1,000 LEDS for $7. Plenty to screw around with.
Your 'Chains' may need only need 4 or 5 LEDs, they also may need 7 or 8. Even though they're 2 volts, and the math works, sometimes the electrical doesnt.
You're reading my line-break, you are a loser. Lurch <3's the c**k.
thanks for the advice, i am looking at an even drop accross each (even output from each) and it looks like with the standard 5mm 2volt LEDs with a 1k Ohm resister wired in parallel would be the best way to do what i need
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
talk to raptor he knows his LEDs, hes actually making kits
hey man has been awhile...ive been good how bout you?
anyway...i got lucky..i happen to be at radioshack the only day that someone was working that knew what they were talking about
i have been doing good, cars coming along slow, modding has come to a hault unfortunately, running out of cash a lot lately, po kit's yet to go on, WW sides yet to go on, RK front and rear lips yet to be bought, 350 to finish body work including trunk shavage. and another 450-500 to finish buttonning up my system. so im in a hole here. BUT back on topic..... raptor had e mailed me, but didnt answer everything i wanted to know, waiting on another response from him... so far general concensus seems to be that 5mm 2 volt LEDs with 460ohm resistors wired in parallel...
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
1Bad02Cav wrote:standard 5mm 2volt LEDs with a 1k Ohm resister wired in parallel would be the best way to do what i need
You mean in series. In parallel would do nothing at all since both the LEDs as well as the resistor complete the circuit.
Also the statement about putting 6 LEDs in series and the first one will be the brightest? not true. As long as all LEDs are rated the same, they will all be equally bright. If you use Ohm's law to figure out the voltage drops and current through each LED in the circuit, you will see that there is equal drop arcoss each LED in the circuit.
you got it backwards, if u wire them in series, the second LED will only get whats left of the power after the drop across the first, adn 3rd will only get whats left of that, so yes, the first in a series will be brighter. in parallel, your doing it similar to a Distribution block for amp powering, the power comes in and evenly splits to each LED
On the other hand....you have other fingers.
i had lots of toys when i was young.slinky,etc.but once i found my penis,that was all she wrote
Nope....do the math. If you build out a circuit and all resistance loads are equal and wired in series, each load will have an equal amount of voltage drop. Equal voltage drop means equal power to each load.
For example, say you have a 12V battery and 4 100 Ohm loads wired in series. If you do Ohm's Law, I=E/R, you get a current of 0.03Amps through the circuit.
I=E/R = 12/400 = 0.03
This means that there is 30mA flowing through the circuit. Every load is passing the exact same current since they are in series.
Therefore you can continue to break down the circuit with Ohm's Law and you can find the voltage drop across each load.
E=IR = 0.03 * 100 = 3Volts
There is a 3 volt drop across each load item. Continuing with Ohm's Law.
P=EI = 3 * 0.03 = 0.09 Watts
That means that each of the 4 100 Ohm loads is using 90mWatts of power. Equal power usage across all 4 load items.
Ohm's Law Reference
